x^2-12x-425=0

Solution for x^2-12x-425=0 equation:

x^2-12x-425=0

a = 1; b = -12; c = -425;
Δ = b2-4ac
Δ = -122-4·1·(-425)
Δ = 1844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1844}=\sqrt{4*461}=\sqrt{4}*\sqrt{461}=2\sqrt{461}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{461}}{2*1}=\frac{12-2\sqrt{461}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{461}}{2*1}=\frac{12+2\sqrt{461}}{2}
$